Please help urgently!!! 2x(squared)+x-3=0 5x(squared)+3x=2x(squared)-5x=05x(squared)= 4x These are all separate equations, can somebody solve them?!
Accepted Solution
A:
[Note: ^2 is squared. i just find it quicker to type out]
2x^2 + x - 3 = 0 First get rid of -3 by adding 3 to both sides. 2x^2 + x = +3 Then get rid of x by subtracting x from both sides 2x^2 = 3 - x Now square root (β) both sides to get rid of the square (^2). This leaves 2x by itself. 2x = β(3 - x) Finally, divide both sides by 2 so x can be by itself. x = β(3 - x)/2
5x^2 + 3x =2 Similar to question the 1st question. Get rid of -3x because its smaller than 5x^2 5x^2 = 2 + 3x Now get rid of the square by sq rooting both sides 5x = β(2 -3x) This time you divide both sides by 5 x = β(2 - 3x)/5
x^2 - 5x = 0 +5x to both sides x^2 = 5x sq root both sides to remove ^2 x = β(5x) I think this part is optional since you've already got x by itself, but you could divde both sidee by 5 so its not 5x x/5 = βx